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If hcf of 384 and 26 is 2 find m,n such that 2=m×384+n×26 where m and n Faq equal 3_4_1_20 – math faq
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 %5C%5C 2 %3D 20 - (26 - 20)3 %5C%5C 2 %3D 384 - 26 %5Ctimes 14 - 26 %5Ctimes 3 %2B 20 %5Ctimes 3 %5C%5C 2 %3D 384 - 26 %5Ctimes 17 %2B (384 - 26 %5Ctimes 14) %5Ctimes 3 %5C%5C 2 %3D 384 %2B 384 %5Ctimes 3 - 26 %5Ctimes 17 - 26 %5Ctimes 42 %5C%5C 2 %3D (4)384%2B ( - 59) %5Ctimes 26 %5C%5C )
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